|
[Date Index]
[Thread Index]
[Author Index]
Re: Is -1^(2/5) really undefined in R?
- To: mathgroup at smc.vnet.net
- Subject: [mg69097] Re: [mg69075] Is -1^(2/5) really undefined in R?
- From: János <janos.lobb at yale.edu>
- Date: Wed, 30 Aug 2006 06:32:45 -0400 (EDT)
- References: <200608290847.EAA00784@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
On Aug 29, 2006, at 4:47 AM, Ben wrote:
> Is -1^(2/5) really undefined in R?
>
> Mathematica seems to think so, I guess since it looks like a
> negative square root, but
>
> -1^(2/5) = (-1^2)^(1/5) = 1^(1/5) = 1
>
> Is this correct mathematically?
>
> cheers,
>
> BC
On my machine:
In[1]:=
-1^(2/5)
Out[1]=
-1
In[6]:=
(-1)^(2/5)
Out[6]=
(-1)^(2/5)
I think your first equal sign is incorrect. it should be -(1)^2^
(1/5), but hey, I was never good in mathematics :)
János
Prev by Date:
Re: restart?
Next by Date:
Re: General--Using FindRoot
Previous by thread:
Is -1^(2/5) really undefined in R?
Next by thread:
Re: Is -1^(2/5) really undefined in R?
|