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Re: Is -1^(2/5) really undefined in R?


version= Mathematica 5.1, Windows

Hi Ben,

There are actually five values of -1^(2/5), one of which is real.

Consider -1=Exp[I (Pi + 2 n Pi)]. Then -1^(2/5)=Exp[2/5 I(I Pi + 2 n Pi)]

Well, which value will mathematica return. You can find the answer in 

the manual under Power: "Power gives the principal value of a Exp[y 

Log[x]]", this is unfortunately not 1 as you expected, but on of the 

complex values.



Daniel



Ben wrote:

> Is -1^(2/5) really undefined in R?

> 

> Mathematica seems to think so, I guess since it looks like a negative square root, but

> 

> -1^(2/5) = (-1^2)^(1/5) = 1^(1/5) = 1

> 

> Is this correct mathematically?

> 

> cheers,

> 

> BC

> 



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