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Re: Making plots using transformation rules
*To*: mathgroup at smc.vnet.net
*Subject*: [mg71950] Re: Making plots using transformation rules
*From*: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
*Date*: Tue, 5 Dec 2006 06:04:54 -0500 (EST)
*Organization*: The Open University, Milton Keynes, UK
*References*: <el128e$5h8$1@smc.vnet.net>
amannuc at yahoo.com wrote:
> I've read about making plots of functions, for example:
>
> Plot[Evaluate[f[x]], {x, 0, 10}]
>
> I don't have this sort of function to plot. Because it involves
> derivatives, I only get numerical output after defining a
> transformation rule. A simple example (not the real one) is the
> following:
>
> g[t_] := D[t^2, t]
> g[t] /. t -> 1
>
> I cannot evaluate g[1], because then Mathematica thinks I am trying to
> take a derivative with respect to the number 1, and flags that as
> error. So I need the transformation rule to get function values.
>
> What is the best way to plot g[t]? I am looking to create multiple
> transformation rules that replace the argument t with a reasonable
> range of values. Then I can plot g[t] versus t. Plot will not do this
> directly because it takes variable values as input. However, as I've
> said, the construction g[x] (x = some number) flags an error.
>
> Thanks for your help.
>
If the argument is always a number, you could define g[t] with a Set
rather than a SetDelayed, or evaluate the derivative directly within the
plot command.
In[1]:=
g[(t_)?NumberQ] = D[t^2, t];
g[1]
Plot[g[x], {x, 0, 10}]
Out[2]=
2
Out[3]=
Graphics
In[4]:=
Plot[Evaluate[D[t^2, t]], {t, 0, 10}]
Out[4]=
Graphics
Regards,
Jean-Marc
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