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Re: Problems with Set, SetDelayed and replacement rules...
*To*: mathgroup at smc.vnet.net
*Subject*: [mg72294] Re: Problems with Set, SetDelayed and replacement rules...
*From*: dh <dh at metrohm.ch>
*Date*: Tue, 19 Dec 2006 06:35:02 -0500 (EST)
*References*: <em3a6c$7fq$1@smc.vnet.net>
Hi Johannes,
there is nothing wrong with your treatment of parameters, but you have
to pay attentio to function arguments. Consider: f[p_]:=Print[p].
If you set p to some value: p=1, what would you expect to be printed by:
f[2]. Well, after you got this, we can fix f3. We have to explicitely
bring "p" into the definition, exactly what f1=.. and f2:=.. do. You
could e.g. use Evaluate:
f3[x_, p_] := Evaluate[f[x] /. params]
Daniel
Johannes wrote:
> Hi,
>
> I am working a lot with physics equations where I have on the one hand variables, and on the other hand paramters, which depend on other parameters which are only given by a polynome.
> In the following (very simplified example) f is a function which depends on variable x and parameters g and h which depend both on parameter p:
>
> f[x_]:= g/h*x;
> g[p_]= 1+p;
> h[p_]=1+p^2;
> params={g->g[p],h->h[p]};
>
> For numerical application, I would like to define a second function f with p as second variable. This I have done with different methods, and there I noticed a difference that I can't explain
>
> f1[x_, p_] = f[x] /. params;
> f2[x_, p_] := f[x] /. {g->g[p],h->h[p]};
> f3[x_, p_] := f[x] /. params;
>
> If I am now calculating f1[1,1], f2[1,1] and f3[1,1], f1 and f2 deliver as expected a numerical value, but for f3[1,1] p isn't replaced by its value 1.
>
> Can anybody explain me the differences, especially the differences between f2 and f3? I suspected it to be exactly identical.
>
> And does anybody know a better method to treat parameters? My problem is that when doing analytical transformations (Derivatives, Integrations...), an immediate replacement of the parameters g and h would make the result very hard to read, so I was searching for an easy method to replace them as late as possible.
>
> Thanks in advance for any help,
> Johannes
>
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