Re: Utilizing the Result From Solve[]
- To: mathgroup at smc.vnet.net
- Subject: [mg64113] Re: [mg64099] Utilizing the Result From Solve[]
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Thu, 2 Feb 2006 00:04:58 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
Clear[z];
z=z/.Solve[z+2==3,z][[1]]
1
Bob Hanlon
>
> From: Shyam Guthikonda <shyamguth at gmail.com>
To: mathgroup at smc.vnet.net
> Subject: [mg64113] [mg64099] Utilizing the Result From Solve[]
>
> If I am solving a simple equation, such as: Solve[z+2 = = 3,z], this
> returns {{z->1}}. How can I easily get the result, 1? Solve[] returns
> the solution in rule form.
>
> The current method I use to just get the result looks very ugly. Is
> there an easier way to do this?
>
> Here is my current method:
>
> ReplaceAll[z, First[ First[ Solve[ z + 2 = = 3, z ]]]];
> z = %;
>
> Now I can use z as a normal variable.
>
> Thanks!
> _Shyam
>
>