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MathGroup Archive 2006

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Re: Utilizing the Result From Solve[]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg64113] Re: [mg64099] Utilizing the Result From Solve[]
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Thu, 2 Feb 2006 00:04:58 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

Clear[z];
z=z/.Solve[z+2==3,z][[1]]

1


Bob Hanlon

> 
> From: Shyam Guthikonda <shyamguth at gmail.com>
To: mathgroup at smc.vnet.net
> Subject: [mg64113] [mg64099] Utilizing the Result From Solve[]
> 
> If I am solving a simple equation, such as: Solve[z+2 = = 3,z], this 
> returns {{z->1}}. How can I easily get the result, 1? Solve[] returns 
> the solution in rule form.
> 
> The current method I use to just get the result looks very ugly. Is 
> there an easier way to do this?
> 
> Here is my current method:
> 
> ReplaceAll[z, First[ First[ Solve[ z + 2 = = 3, z ]]]];
> z = %;
> 
> Now I can use z as a normal variable.
> 
> Thanks!
> _Shyam
> 
> 


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