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MathGroup Archive 2006

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Re: Utilizing the Result From Solve[]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg64133] Re: Utilizing the Result From Solve[]
  • From: Helen Read <hpr at together.net>
  • Date: Thu, 2 Feb 2006 00:06:16 -0500 (EST)
  • References: <drq0gm$mr6$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Shyam Guthikonda wrote:
> If I am solving a simple equation, such as: Solve[z+2 = = 3,z], this 
> returns {{z->1}}. How can I easily get the result, 1? Solve[] returns 
> the solution in rule form.
> 
> The current method I use to just get the result looks very ugly. Is 
> there an easier way to do this?
> 
> Here is my current method:
> 
> ReplaceAll[z, First[ First[ Solve[ z + 2 = = 3, z ]]]];
> z = %;
> 
> Now I can use z as a normal variable.

z = z /. Solve[z + 2 == 3, z][[1]]

Though personally, I would name the specific result something like z1 
instead of z, like this.

z1= z /. Solve[z + 2 == 3, z][[1]]

This way you can go on to solve *other* equations involving the variable 
z (giving the solutions different names) without having to Clear[z].

-- 
Helen Read
University of Vermont


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