Re: Trigonometric form of complex numbers

*To*: mathgroup at smc.vnet.net*Subject*: [mg64190] Re: Trigonometric form of complex numbers*From*: Omega Consulting <info at omegaconsultinggroup.com>*Date*: Sat, 4 Feb 2006 04:13:47 -0500 (EST)*References*: <200602030603.BAA15931@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Expanding on that, you can have complex numbers printed in this form by default. (Note, this only changes the printout. Internally, it's still stored as a complex number.) MakeBoxes[z_Complex, StandardForm] := ToBoxes[Abs[z] HoldForm[E]^(HoldForm[I] Arg[z]), StandardForm] N[Solve[x^3 == -1, x]] {{x -> -1.}, {x -> 1. E^(1.0472 I)}, {x -> 1. E^(1.0472 I)}} ---------------------------------------------- Omega Consulting The final answer to your Mathematica needs. http://omegaconsultinggroup.com On Feb 3, 2006, at 12:03 AM, Bob Hanlon wrote: > polar[x_]:=Abs[x]*Exp[I*Arg[x]]; > > polar/@(x/.Solve[x^3==-1,x]) > > {-1, E^((I*Pi)/3), E^(-((I*Pi)/3))} > > > Bob Hanlon > >> >> From: ivan.svaljek at gmail.com To: mathgroup at smc.vnet.net >> Subject: [mg64190] [mg64166] [mg64158] Trigonometric form of complex numbers >> >> Is there a way to force mathematica to output complex numbers in >> trigonometric form (I guess you call it Phasor). >> Can it return all 3 roots of a complex number in such a form ? >> >> Thanks. >> >>

**References**:**Re: Trigonometric form of complex numbers***From:*Bob Hanlon <hanlonr@cox.net>