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MathGroup Archive 2006

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Re: finding the position of a pattern in list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg64610] Re: [mg64583] finding the position of a pattern in list
  • From: jmt <jmt at dxdydz.net>
  • Date: Fri, 24 Feb 2006 00:18:06 -0500 (EST)
  • Organization: dxdydz
  • References: <200602230534.AAA13180@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

On Thursday 23 February 2006 06:34, Gang Ma wrote:
> Hi,
> I am working on a program to do the following: My data is a list of 0
> and 1. For example, {0,0,1,1,1,0,0,1,1,1,0}. I want to find the
> positions of all the pattern of {0,1}.  In my previous example, the
> first {0,1} is at 2 and and the second {0,1} appears at 7. I can
> write a loop to do this, but I have several thousands such lists,
> the computation will be time consuming using loop.


Try this :

your data :
myList = {0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0}
myPattern = List[0, 1]

this generates all pairs built with consecutive elements :
Partition[myList, 2, 1]

this gives the expected result :
Position[Partition[myList, 2, 1], myPattern]


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