Re: Getting the small parts right or wrong. Order and Collect
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- Subject: [mg63631] Re: Getting the small parts right or wrong. Order and Collect
- From: "Richard Fateman" <fateman at cs.berkeley.edu>
- Date: Sun, 8 Jan 2006 03:32:52 -0500 (EST)
- References: <dpg11e$pm4$1@smc.vnet.net> <dplhq9$em8$1@smc.vnet.net> <200601070729.CAA06924@smc.vnet.net> <6FCF3227-C4E1-418A-BAC1-F3981F969878@mimuw.edu.pl> <dpo3gp$gaq$1@smc.vnet.net>
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"Andrzej Kozlowski" <akoz at mimuw.edu.pl> wrote in message news:dpo3gp$gaq$1 at smc.vnet.net... > On 7 Jan 2006, at 18:04, Andrzej Kozlowski wrote: > >> >> >> There is one very simple thing you can do, which I think completely >> deals with your problem. >> You can convert the output to TraditionalForm. >> No, because TraditionalForm is only a hack on the display. If you pick out the parts of the expression in sequence by using %[[1]] etc, you find that the coefficients of the different powers of x are picked out in the StandardForm order, not the TraditionalForm order. Putting the coefficients in an array is plausible, but Andrzej other solution, which is 1 + Plus @@ Table[Coefficient[(1 + x + y)^3, x^i]*x^i, {i, 1, 3}] is wrong because it results in answers in the order 1, x^3, x^2, x. And of course picking out the coefficient of "1". Along those lines it is better to do ... Table[Coefficient[(1+x+y)^3,x,i] ,{i,0,3}] where i can also be 0. And the table keeps the coefficients from being randomly sorted. "Of course there is no way to make the powers of x ascend as you originally seems to have wanted but then we can't have everything even where Mathematica is concerned." Eh, this one can be solved with Table and Coefficient. It is just that the EXAMPLE IN THE BOOK is the mistake. RJF
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- From: Andrzej Kozlowski <akoz@mimuw.edu.pl>
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- Getting the small parts right or wrong. Order and Collect
- From: "Richard Fateman" <fateman@cs.berkeley.edu>
- Getting the small parts right or wrong. Order and Collect