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Re: Assuming to be a real number is useless even in simple cases?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg63951] Re: [mg63945] Assuming to be a real number is useless even in simple cases?
  • From: "Erickson Paul-CPTP18" <Paul.Erickson at Motorola.com>
  • Date: Wed, 25 Jan 2006 04:11:22 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Because the function Im doesn't make assumptions (or more appropriate
take $Assumptions). That is assumptions are used by Simplify, Integrate,
Refine, ? Others ? , but not Im.

Therefore  Assuming[x\[Element]Reals, Im[x]] is not substantially
different from just Im[x].

However, Simplify does take arguments, so "Assuming[x\[Element]Reals,
Simplify[ Im[x] ] ] " is "0".

Paul


-----Original Message-----
From: Roberto [mailto:roberto at pop.it] 
To: mathgroup at smc.vnet.net
Subject: [mg63951] [mg63945] Assuming to be a real number is useless even in
simple cases? 

In[1]:=
Assuming[x\[Element]Reals, Im[x]]

Out[1]=
Im[x]

Why it's not zero?


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