Re: orthonormal eigenvectors
- To: mathgroup at smc.vnet.net
- Subject: [mg67621] Re: [mg67576] orthonormal eigenvectors
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Sun, 2 Jul 2006 06:28:06 -0400 (EDT)
- References: <200607010912.FAA20405@smc.vnet.net> <024C3AAB-F15C-41D1-8357-BF61A00C9252@mimuw.edu.pl> <Pine.LNX.4.58.0607020937060.4262@mp.okayama-u.ac.jp>
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But this example is no good, since this matrix is not symmetric (real hermitian). A real symmetric matrix can be diagonalized by an orthognonal matrix. This is not true for arbitrary real matrics. Andrzej Kozlowski On 2 Jul 2006, at 09:48, tkghosh wrote: > > > Thanks for your reply and sorry for not giving an example. > > I am giving here a simple example of 6 X 6 matrix, although the > actual matrix is 11 X 11 matrix. > > Suppose 6 X 6 matrix is the following: > > M = {{306.25, -306.25, 0, 0, 0, 0},{-102.083, 310.25, -204.167, 0, > 0, 0}, > {0, -122.5, 318.25, -183.75, 0, 0}, {0, 0, -131.25, 330.25, > -175.,0}, > {0, 0, 0, -136.111, 346.25, -170.139}, {0, 0, 0, 0, -139.205, > 366.25}} > > > > {w, v} = Eigensystem[M]; (* "w" is the Eigenvalues and "v" > Eigenvectors *) > > v[[6]].v[[5]] = -0.57199 > > v[[6]].v[[3]] = 0.327911 > > v[[6]].v[[1]] = -0.15311 > > It cleary shows that the vectors are not orthogonal. > However, these vectors are normalized. > You are correct that the matirx M has a pecuiliar shape and > I must use some other subtle method to compute them. Do not > know what method is most suitable. > > Do you have any idea how to solve that kind of matrix (M) and > how to get an orthogonal vectors? > > Any help is welcome. > > Thanking you again. > Tarun
- References:
- orthonormal eigenvectors
- From: tkg <tkghosh@mp.okayama-u.ac.jp>
- orthonormal eigenvectors