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Re: Iterated Function System

  • To: mathgroup at smc.vnet.net
  • Subject: [mg67706] Re: Iterated Function System
  • From: Roger Bagula <rlbagula at sbcglobal.net>
  • Date: Wed, 5 Jul 2006 04:17:59 -0400 (EDT)
  • References: <e8d0uo$4dk$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Here's one that uises Mark McClure's "DigraphFractals`":
it calculates the dimension as well as the fractal for a Rauzy tile:
( I didn't change the base name" terdragonDigraph" that Dr. McClure used!)
Solve[x^3-x^2-x-1==0,x]

NSolve[x^3-x^2-x-1==0,x]
c=-0.419643377607080569
s=-0.606290729207199419
z=c+I*s
z^2
c1=-0.19148788395311880508967465797
s1=0.50885177883273803553625813551
z^3
c2=0.38886873843980076415946686483
s2=-0.09743895037446135435716873396
rotate[theta_] := {{Cos[theta], -Sin[theta]},
    {Sin[theta], Cos[theta]}};
f = {{{c,-s},{s,c}},{c,s}};
g = {{{c1,-s1},{s1,c1}},{c1,s1}};
h = {{{c2,-s2},{s2,c2}},{c2,s2}};

Needs["DigraphFractals`"];


terdragonDigraph = {{{f, g, h}}}

ShowDigraphFractals[terdragonDigraph, 9];
ComputeDimension[terdragonDigraph]


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