Re: Why does Reduce work this way ...?
- To: mathgroup at smc.vnet.net
- Subject: [mg67251] Re: Why does Reduce work this way ...?
- From: Bill Rowe <readnewsciv at earthlink.net>
- Date: Wed, 14 Jun 2006 06:29:14 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
On 6/13/06 at 1:07 AM, jackgoldberg at comcast.net wrote: >This post is related to a previous series of posts about ReplaceAll >in a set of inequalities. I have "reduced" the problem to this >unexpected situation: >In[1] FullForm[-3<=x<=1] >Out[1] LessEqual[-3,x,1] >In[2] Reduce[-3<=x<=1] Out[2] -3<=x<=1 >In[3] FullForm[%2] >Out[3] Inequality[-3, LessEqual, y, LessEqual,1] >In[4] Reduce[ LessEqual[-3,x,1] >Out[4] -3 ≤ x ≤ 1 >In[5] FullForm[%4] >Out[5] Inequality[-3, LessEqual, y, LessEqual,1] >This defies my understanding. What is qoing on with Reduce? Hmm... You didn't say what version of Mathematica you are using. With In[13]:= $Version Out[13]= 5.2 for Mac OS X (June 20, 2005) I get In[14]:= Reduce[LessEqual[-3,x,1]] Out[14]= -3 <= x <= 1 and since In[15]:= Inequality[-3,LessEqual,x,LessEqual,1] Out[15]= -3 <= x <= 1 I am not seeing any inconsistency -- To reply via email subtract one hundred and four