|
[Date Index]
[Thread Index]
[Author Index]
Re: Why does Reduce work this way ...?
- To: mathgroup at smc.vnet.net
- Subject: [mg67236] Re: Why does Reduce work this way ...?
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Wed, 14 Jun 2006 06:28:40 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
- References: <e6lhul$nh2$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
jackgoldberg at comcast.net wrote:
> Hi folks,
>
> This post is related to a previous series of posts about ReplaceAll in a set of inequalities.
> I have "reduced" the problem to this unexpected situation:
>
> In[1] FullForm[-3<=x<=1]
> Out[1] LessEqual[-3,x,1]
>
> In[2] Reduce[-3<=x<=1]
> Out[2] -3<=x<=1
>
> In[3] FullForm[%2]
> Out[3] Inequality[-3, LessEqual, y, LessEqual, 1]
>
> In[4] Reduce[ LessEqual[-3,x,1]
> Out[4] -3 ≤ x ≤ 1
>
> In[5] FullForm[%4]
> Out[5] Inequality[-3, LessEqual, y, LessEqual, 1]
>
> This defies my understanding. What is qoing on with Reduce?
>
> Jack
>
Hi Jack,
Yes, your results seem rather puzzling! I don not know from where you
can possibly get the 'y' especially with a freshly started Mathematica
session...
On my system everything is fine, no 'y'
In[1]:=
FullForm[-3 <= x <= 1]
Out[1]//FullForm=
LessEqual[-3, x, 1]
In[2]:=
Reduce[-3 <= x <= 1]
Out[2]=
-3 <= x <= 1
In[3]:=
FullForm[%2]
Out[3]//FullForm=
Inequality[-3, LessEqual, x, LessEqual, 1]
In[4]:=
Reduce[-3 <= x <= 1]
Out[4]=
-3 <= x <= 1
In[5]:=
FullForm[%4]
Out[5]//FullForm=
Inequality[-3, LessEqual, x, LessEqual, 1]
In[6]:=
$Version
Out[6]=
5.2 for Microsoft Windows (June 20, 2005)
Best regards,
/Jean-Marc
Prev by Date:
Re: new slide template: how change?
Next by Date:
Re: Determining continuity of regions/curves from inequalities
Previous by thread:
Re: Why does Reduce work this way ...?
Next by thread:
Determining continuity of regions/curves from inequalities
|