Re: Integrate with multiple integrals -- bug?

*To*: mathgroup at smc.vnet.net*Subject*: [mg67409] Re: Integrate with multiple integrals -- bug?*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Thu, 22 Jun 2006 06:21:36 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

On 6/21/06 at 2:12 AM, ms_usenet at gmx.de (Martin Schoenecker) wrote: >I am wondering where my or Mathematica's error in reasoning lies: >In[1]:= Integrate[g[z], {x, 0, a}] >Out[1]= a*g[z] >ok, because the function g does not depend on x. >In[2]:= Integrate[g[z], {z, 0, c}] >Out[2]= Integrate[g[z], {z, 0, c}] >ok, function g is not specified at the moment. >In[3]:= Integrate[g[z], {z, 0, c}, {x, 0, a}] >Out[3]= Integrate[a*g[z], {z, 0, c}] >also ok. Now with the integration order reversed: >In[4]:= Integrate[g[z], {x, 0, a}, {z, 0, c}] >Out[4]= a*g[z] >?? why this result ?? What version of Mathematica are you using. With In[7]:= $Version Out[7]= 5.2 for Mac OS X (June 20, 2005) I get In[6]:= Integrate[g[z],{z,0,c},{x,0,a}]==Integrate[g[z],{x,0,a},{z,0,c}] Out[6]= True That is, I get the same output as your Out[3] above regardless of the order of integration. -- To reply via email subtract one hundred and four