Re: Solving Nonlinear Transcedental equations

*To*: mathgroup at smc.vnet.net*Subject*: [mg66152] Re: [mg66103] Solving Nonlinear Transcedental equations*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Mon, 1 May 2006 01:30:42 -0400 (EDT)*Reply-to*: hanlonr at cox.net*Sender*: owner-wri-mathgroup at wolfram.com

From Help for FindRoot "FindRoot[lhs == rhs, {x, x0, x1}] searches for a solution using x0 and x1 as the first two values of x, avoiding the use of derivatives." {#, 0, 0.001}&/@{a, b, c, d, e} maps the form onto the list of variables to give them all the same two starting values. (See Help for Map, Function, Slot) Bob Hanlon ---- shyam d <shyam.nitk at gmail.com> wrote: > Thanks for sending me the solution. > but,in the command FindRoot[eqns,{#,0,0.001}&/@{a,b,c,d,e}, > WorkingPrecision->25] > I would like to know what is the meaning of #,0,0.001. > Is that indicates any accuracy. > Once again thank you > > On 4/30/06, Bob Hanlon <hanlonr at cox.net> wrote: > > > > eqns={Cos[5a]+Cos[5b]+Cos[5c]+Cos[5d]+Cos[5e]==0 , > > Cos[7a]+Cos[7b]+Cos[7c]+Cos[7d]+Cos[7e]==0 , > > Cos[11a]+Cos[11b]+Cos[11c]+Cos[11d]+Cos[11e]==0 , > > Cos[13a]+Cos[13b]+Cos[13c]+Cos[13d]+Cos[13e]==0 , > > Cos[a]+Cos[b]+Cos[c]+Cos[d]+Cos[e]==4}; > > > > soln=FindRoot[eqns,{#,0,0.001}&/@{a,b,c,d,e}, > > WorkingPrecision->25] > > > > {a -> 0.3305683994360862122301429, > > b -> 0.1146653314898035411913792, > > c -> -0.7877678437228476935626191, > > d -> -0.4744373833069562315667576, > > e -> 1.086337197092250719345098} > > > > > > Bob Hanlon > > > > > > ---- shyam d <shyam.nitk at gmail.com> wrote: > > > > > > I got a problem with Mathematica 5.1 ,as i am going to solve a Nonlinear > > > Transcedental Equations, which are five variables with five eqations.itis > > > not able to solve the problem and it is not showing any thing can any > > > on please solve the problem using mathematica 5.1. > > > and send me how to solve in mathematica 5.1 > > > The problem statement is > > > > > > solving the 5 simultaneous Non linear Transcedental equations > > > > > > cos(5a)+cos(5b)+cos(5c)+cos(5d)+cos(5e)=0 > > > cos(7a)+cos(7b)+cos(7c)+cos(7d)+cos(7e)=0 > > > cos(11a)+cos(11b)+cos(11c)+cos(11d)+cos(11e)=0 > > > cos(13a)+cos(13b)+cos(13c)+cos(13d)+cos(13e)=0 > > > cos(a)+cos(b)+cos(c)+cos(d)+cos(e)=4 > > > > > > solve for a= ?,b= ?,c= ?,d= ? > > > > > > thanks > > > shaym > > > > > > > > > >