Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2006
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2006

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: )

  • To: mathgroup at smc.vnet.net
  • Subject: [mg66313] Re: )
  • From: Maxim <m.r at inbox.ru>
  • Date: Tue, 9 May 2006 02:35:08 -0400 (EDT)
  • References: <200605050902.FAA28575@smc.vnet.net> <e3hf84$m1h$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

On Sat, 6 May 2006 06:20:52 +0000 (UTC), Andrzej Kozlowski  
<akoz at mimuw.edu.pl> wrote:

>
> laws of arithmetic do not hold). Some of them are hard to explain: I
> can't see any good reason at all why Infinity^Infinity is
> ComplexInfinity, and it seems to contradict the the most basic rule
> that x^y is always real when x and y are positive reals. Besides, as
> I mentioned earlier, Infinity and ComplexInfinity do not belong
> together in any topological model known to me (you need a
> "topological model" to be able to consider the issue of continuity)
> and should never appear in the same formula. I can only consider this
> as a bug, and a rather silly one.
>

I think this is as it should be: we need to consider all the sequences  
converging to Infinity, and, for example, Limit[(x + I*Pi)^x, x ->  
Infinity] == -Infinity. So in that sense Infinity^Infinity ==  
ComplexInfinity: when z = z1^z2 and z1, z2 go to Infinity the absolute  
value of z always tends to Infinity but the argument can be arbitrary.

Maxim Rytin
m.r at inbox.ru


  • Follow-Ups:
    • Re: Re: )
      • From: Andrzej Kozlowski <akoz@mimuw.edu.pl>
  • Prev by Date: Re: How to set up "Do" or "While" loops for several seperate commands
  • Next by Date: Re: 3D surface plotting
  • Previous by thread: Re: When is x^y = != E^(y*Log[x])
  • Next by thread: Re: Re: )