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Re: Interval[{a,b}]-Interval[{a,b}] = 0?


>Is this a bug or a feature?
>Notice that Interval[{-1,1}]-Interval[{-1,1}] is Interval>[{-2,2}].
>
>(I'm using Mathematica 5.1)
>
>RJF

Hi Richard,

The sum I + J is defined as
I + J = {i+j : i in I, j in J}
for sets I and J in IR.

So I - I = 2*I is correct for I = [-1;1].

Best wishes
Torsten.


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