Re: Interval[{a,b}]-Interval[{a,b}] = 0?

*To*: mathgroup at smc.vnet.net*Subject*: [mg66635] Re: Interval[{a,b}]-Interval[{a,b}] = 0?*From*: "Borut Levart" <BoLe79 at gmail.com>*Date*: Thu, 25 May 2006 02:57:54 -0400 (EDT)*References*: <e510r2$8eg$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

When subtracting an Interval[{c,d}] from Interval [{a,b}], i.e.: [a,b] - [c,d] I imagine "all the possibilities", and "all" in this case means subtracting d from a and c from b. That is the "worst case scenario". So the resulting interval would be: [a-d,b-c] Mind that Interval[{a,b}] represent a number of numbers. The result of subtraction cannot be a single number, but an interval. Bye, Borut Levart Slovenia