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Re: Interval[{a,b}]-Interval[{a,b}] = 0?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg66635] Re: Interval[{a,b}]-Interval[{a,b}] = 0?
  • From: "Borut Levart" <BoLe79 at gmail.com>
  • Date: Thu, 25 May 2006 02:57:54 -0400 (EDT)
  • References: <e510r2$8eg$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

When subtracting an Interval[{c,d}] from Interval [{a,b}], i.e.:
[a,b] - [c,d]
I imagine "all the possibilities", and "all" in this case means
subtracting d from a and c from b. That is the "worst case scenario".
So the resulting interval would be:

[a-d,b-c]

Mind that Interval[{a,b}] represent a number of numbers. The result of
subtraction cannot be a single number, but an interval.

Bye,
Borut Levart
Slovenia


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