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Re: Interval[{a,b}]-Interval[{a,b}] = 0?


When subtracting an Interval[{c,d}] from Interval [{a,b}], i.e.:
[a,b] - [c,d]
I imagine "all the possibilities", and "all" in this case means
subtracting d from a and c from b. That is the "worst case scenario".
So the resulting interval would be:

[a-d,b-c]

Mind that Interval[{a,b}] represent a number of numbers. The result of
subtraction cannot be a single number, but an interval.

Bye,
Borut Levart
Slovenia


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