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Re: Interval[{a,b}]-Interval[{a,b}] = 0?


On 24 May 2006, at 16:01, Richard Fateman wrote:

> Is this a bug or a feature?
> Notice that Interval[{-1,1}]-Interval[{-1,1}] is Interval[{-2,2}].
>
> (I'm using Mathematica 5.1)
>
> RJF
>

I get

Interval[{-1,1}]-Interval[{-1,1}]


Interval[{-2,2}]

In[6]:=
$Version

Out[6]=
5.1 for Mac OS X (October 25, 2004)

This is most certainly correct (as, I think, you point out in your  
post). So whatever you have found, is neither a bug or a feature of  
my copy of Mathematica 5.1. Hmm... perhaps they have some "cracked"  
copies of Mathematica at Berkley? ;-)

Andrzej Kozlowski
Tokyo, Japan


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