Re: Interval[{a,b}]-Interval[{a,b}] = 0?

*To*: mathgroup at smc.vnet.net*Subject*: [mg66633] Re: [mg66613] Interval[{a,b}]-Interval[{a,b}] = 0?*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>*Date*: Thu, 25 May 2006 02:57:49 -0400 (EDT)*References*: <200605240701.DAA08477@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

On 24 May 2006, at 16:01, Richard Fateman wrote: > Is this a bug or a feature? > Notice that Interval[{-1,1}]-Interval[{-1,1}] is Interval[{-2,2}]. > > (I'm using Mathematica 5.1) > > RJF > I get Interval[{-1,1}]-Interval[{-1,1}] Interval[{-2,2}] In[6]:= $Version Out[6]= 5.1 for Mac OS X (October 25, 2004) This is most certainly correct (as, I think, you point out in your post). So whatever you have found, is neither a bug or a feature of my copy of Mathematica 5.1. Hmm... perhaps they have some "cracked" copies of Mathematica at Berkley? ;-) Andrzej Kozlowski Tokyo, Japan

**References**:**Interval[{a,b}]-Interval[{a,b}] = 0?***From:*"Richard Fateman" <fateman@cs.berkeley.edu>