Re: use a function within a new function

• To: mathgroup at smc.vnet.net
• Subject: [mg70954] Re: use a function within a new function
• From: dh <dh at metrohm.ch>
• Date: Thu, 2 Nov 2006 06:49:03 -0500 (EST)
• References: <ei9nuo\$1ps\$1@smc.vnet.net>

```
Hi Aitor,

What you did is o.k., but you fool yourself by choosing different

parameters in the 2 Plots: {t, 0, 9}, {a, 0, 9}, and  {t, 0, 720}, {a,

0, 720}

Daniel

aitor69gonzalez at gmail.com wrote:

> Hello,

>

> I have a function like:

> phi(a,t) = sin(2*pi*(t-a)/T' + a/T)

> where "T" is itself a function of "a" like here:

> ####

> Plot3D[Sin[2*\[Pi]*((t - a)/3 + a/(a + 1))], {t, 0, 9}, {a, 0, 9},

>     AxesLabel -> {"t", "a", "ex"}, Lighting -> False,

>     ViewPoint -> {0, 0, 100}, PlotPoints -> 40, Mesh -> False];

> ####

> Therefore, I would like to define T separately. Something like here:

> ####

> T[a_] = a + 1;

> phi[a_, t_] = Sin[2*\[Pi]*((t - a)/3 + a/T[a])];

> Plot3D[phi[a, t], {t, 0, 720}, {a, 0, 720}, AxesLabel -> {"t", "a",

> "ex"},

>   Lighting -> False, ViewPoint -> {0, 0, 100}, PlotPoints -> 40,

>   Mesh -> False]

> ####

> But as you can see, both plots do not look like the same. How can I

> define a "T" as a function of a separately?

> Thank you in advance.

>

> Aitor

>

```

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