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Re: use a function within a new function
 To: mathgroup at smc.vnet.net
 Subject: [mg70941] Re: use a function within a new function
 From: "JensPeer Kuska" <kuska at informatik.unileipzig.de>
 Date: Thu, 2 Nov 2006 06:47:40 0500 (EST)
 Organization: Uni Leipzig
 References: <ei9nuo$1ps$1@smc.vnet.net>
Hi,
you can't because the region you are ploting is in
the first
case {{t, 0, 9}, {a, 0, 9}}
in the second one {t, 0, 720}, {a, 0, 720}
and you see the difference of a magnification
factor 80
while you will have no problems with an ant, when
you magnify
the ant by a factor of 80 it *will* look
different.
Regards
Jens
<aitor69gonzalez at gmail.com> schrieb im Newsbeitrag
news:ei9nuo$1ps$1 at smc.vnet.net...
 Hello,

 I have a function like:
 phi(a,t) = sin(2*pi*(ta)/T' + a/T)
 where "T" is itself a function of "a" like here:
 ####
 Plot3D[Sin[2*\[Pi]*((t  a)/3 + a/(a + 1))], {t,
0, 9}, {a, 0, 9},
 AxesLabel > {"t", "a", "ex"}, Lighting >
False,
 ViewPoint > {0, 0, 100}, PlotPoints > 40,
Mesh > False];
 ####
 Therefore, I would like to define T separately.
Something like here:
 ####
 T[a_] = a + 1;
 phi[a_, t_] = Sin[2*\[Pi]*((t  a)/3 + a/T[a])];
 Plot3D[phi[a, t], {t, 0, 720}, {a, 0, 720},
AxesLabel > {"t", "a",
 "ex"},
 Lighting > False, ViewPoint > {0, 0, 100},
PlotPoints > 40,
 Mesh > False]
 ####
 But as you can see, both plots do not look like
the same. How can I
 define a "T" as a function of a separately?
 Thank you in advance.

 Aitor

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