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MathGroup Archive 2006

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Re: use a function within a new function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg70942] Re: use a function within a new function
  • From: "." <ggroup at sarj.ca>
  • Date: Thu, 2 Nov 2006 06:47:52 -0500 (EST)
  • References: <ei9nuo$1ps$1@smc.vnet.net>

It does work.  The error is in your two plots; you have chosen
different ranges for your two parameters a & t.  Try these two:

Plot3D[Sin[2*\[Pi]*((t - a)/3 + a/(a + 1))], {t, 0, 9}, {a, 0, 9},
     AxesLabel -> {"t", "a", "ex"}, Lighting -> False,
     ViewPoint -> {0, 0, 100}, PlotPoints -> 40, Mesh -> False];

T[a_] = a + 1;
 phi[a_, t_] = Sin[2*\[Pi]*((t - a)/3 + a/T[a])];
 Plot3D[phi[a, t], {t, 0, 9}, {a, 0, 9}, AxesLabel -> {"t", "a",
"ex"},
   Lighting -> False, ViewPoint -> {0, 0, 100}, PlotPoints -> 40,
   Mesh -> False]


aitor69gonzalez at gmail.com wrote:
> Hello,
>
> I have a function like:
> phi(a,t) = sin(2*pi*(t-a)/T' + a/T)
> where "T" is itself a function of "a" like here:
> ####
> Plot3D[Sin[2*\[Pi]*((t - a)/3 + a/(a + 1))], {t, 0, 9}, {a, 0, 9},
>     AxesLabel -> {"t", "a", "ex"}, Lighting -> False,
>     ViewPoint -> {0, 0, 100}, PlotPoints -> 40, Mesh -> False];
> ####
> Therefore, I would like to define T separately. Something like here:
> ####
> T[a_] = a + 1;
> phi[a_, t_] = Sin[2*\[Pi]*((t - a)/3 + a/T[a])];
> Plot3D[phi[a, t], {t, 0, 720}, {a, 0, 720}, AxesLabel -> {"t", "a",
> "ex"},
>   Lighting -> False, ViewPoint -> {0, 0, 100}, PlotPoints -> 40,
>   Mesh -> False]
> ####
> But as you can see, both plots do not look like the same. How can I
> define a "T" as a function of a separately?
> Thank you in advance.
> 
> Aitor


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