Re: Simple Problem with Polyhedron::Hexahedron

*To*: mathgroup at smc.vnet.net*Subject*: [mg71224] Re: Simple Problem with Polyhedron::Hexahedron*From*: "OtavioCC" <otavio at gmail.com>*Date*: Fri, 10 Nov 2006 06:39:02 -0500 (EST)*References*: <eiuroh$ghn$1@smc.vnet.net>

Hi, I've found the answer :) >From Mathematica manual: "The polyhedra are by default centered at the origin with a unit distance from the origin to the midpoint of the edges." So I need 1/2 = h^2 h = Sqrt[0.5]. The correct way to plot an Hexahedron (or a Cube) is: << Graphics`Polyhedra` des = Polyhedron[Hexahedron, {0, 0, 0}, Sqrt[0.5] {10, 5, 3}]; Show[des, Axes -> True, AxesLabel -> {"x", "y", "z"}]; Bye. On Nov 9, 7:18 am, "OtavioCC" <ota... at gmail.com> wrote: > Hi, > > I've a simple question but I didn't found an answer. I'm trying to draw > a Hexahedron with dimensions (10, 5, 3), centered on {0, 0, 0}. So, > I've been doing this: > > << Graphics`Polyhedra` > > des = Polyhedron[Hexahedron, {0, 0, 0}, {10, 5, 3}]; > Show[des, Axes -> True, AxesLabel -> {"x", "y", "z"}]; > > But it's not working, and the resultant Hexahedron don't have this > dimensions... > > Thanks.