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MathGroup Archive 2006

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Re: Simple Problem with Polyhedron::Hexahedron

  • To: mathgroup at smc.vnet.net
  • Subject: [mg71224] Re: Simple Problem with Polyhedron::Hexahedron
  • From: "OtavioCC" <otavio at gmail.com>
  • Date: Fri, 10 Nov 2006 06:39:02 -0500 (EST)
  • References: <eiuroh$ghn$1@smc.vnet.net>

Hi, I've found the answer :)

>From Mathematica manual: "The polyhedra are by default centered at the
origin with a unit distance from the origin to the midpoint of the
edges." So I need 1/2 = h^2 h = Sqrt[0.5]. The correct way to plot an
Hexahedron (or a Cube) is:

<< Graphics`Polyhedra`

des = Polyhedron[Hexahedron, {0, 0, 0}, Sqrt[0.5] {10, 5, 3}];
Show[des, Axes -> True, AxesLabel -> {"x", "y", "z"}];

Bye.

On Nov 9, 7:18 am, "OtavioCC" <ota... at gmail.com> wrote:
> Hi,
>
> I've a simple question but I didn't found an answer. I'm trying to draw
> a Hexahedron with dimensions (10, 5, 3), centered on {0, 0, 0}. So,
> I've been doing this:
>
> << Graphics`Polyhedra`
>
> des = Polyhedron[Hexahedron, {0, 0, 0}, {10, 5, 3}];
> Show[des, Axes -> True, AxesLabel -> {"x", "y", "z"}];
>
> But it's not working, and the resultant Hexahedron don't have this
> dimensions...
> 
> Thanks.


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