Re: 2 dimension Newton Raphson

• To: mathgroup at smc.vnet.net
• Subject: [mg71244] Re: [mg71218] 2 dimension Newton Raphson
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Sat, 11 Nov 2006 03:39:15 -0500 (EST)

```eqns={(x-4)^2+(y-4)^2==5,x^2+y^2==16};

soln={#[[1]],#[[2]]/.#[[1]]}&/@
{Reduce[eqns,{x,y}]//ToRules}

{{x -> (1/16)*(43 - Sqrt[199]),
y -> (1/8)*(43 + (1/2)*(-43 + Sqrt[199]))},
{x -> (1/16)*(43 + Sqrt[199]),
y -> (1/8)*(43 + (1/2)*(-43 - Sqrt[199]))}}

Needs["Graphics`"];

ImplicitPlot[eqns, {x, -5, 7},
Epilog->{Red, AbsolutePointSize[5],
Point/@({x,y}/.soln)}];

Bob Hanlon

---- ms z <ms-z- at hotmail.com> wrote:
> I have tried to solve the roots of the simultaneous nonlinear equations
> (x-4)^2 + (y-4)^2 = 5
> x^2 + y^2 = 16
>
> by writing this function:
>
> nr2method[xl1_, xl2_, es1_] :=
>   Block[{x1, x2, ea, es, x1new, u, v},
>     u = (x1 - 4)^2 + (x2 - 4)^2 - 5;
>     v = x1^2 + x2^2 - 16;
>     ea = 100; es = es1;
>     For[i = 1, ea > es, i++,
>       (x1new[x1_, x2_] = x1 - (u*D[
>     v, x2] - v*D[u, x2])/(D[u, x1]*D[v, x2] - D[u, x2]*D[v, x1]);
>         If[i == 1, x1 = xl1, x1 = b];
>         x2 = xl2;
>         b = x1new[x1, x2];
>         ea = Abs[(b - x1)/b 100];
>         Clear[x1, x2, x1new];)];
>     ea = 100; es = es1;
>     For[i = 1, ea > es, i++,
>       (x2new[x1_, x2_] = x2 - (v*D[u, x1] - u*D[v, x1])/(D[u, x1]*D[v, x2] -
>         D[u, x2]*D[v, x1]);
>         If[i == 1, x2 = xl2, x2 = c];
>         x1 = xl1;
>         c = x2new[x1, x2];
>         ea = Abs[(c - x2)/c 100];
>         Clear[x1, x2, x2new];)];
>     Print["The value of x1 is ", b];
>     Print["The value of x2 is ", c];]
>
> Is this function a good one? Is there a way to make this function simpler?
>

```

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