MathGroup Archive 2006

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Arithmetic Puzzle (so simple it's hard)

  • To: mathgroup at smc.vnet.net
  • Subject: [mg71324] Re: Arithmetic Puzzle (so simple it's hard)
  • From: "ben" <benjamin.friedrich at gmail.com>
  • Date: Wed, 15 Nov 2006 06:43:17 -0500 (EST)
  • References: <ejc4pv$6nf$1@smc.vnet.net>

Bruce Colletti schrieb:

> How would this problem be solved in Mathematica?
>
> BUT * ASK = FEAST, where each letter is a 1-digit number, no two letters may stand for the same number, and the letters are in {0,1,2,4,5,6,7,9}.
>
> Thankx.
>
> Bruce

Hi Bruce

What about brute-force,
takes only seconds

Do[
  If[
    (Length[Union[{b, u, t, a, s, k, f, e}]] ==
          8) &&
      ((100 b + 10 u + t)(100a + 10s + k) ==
          10000f + 1000 e + 100 a + 10 s + t),
    Print[b, u, t, a, s, k, f, e, a, s, t]],
  {b, 1, 9}, {u, 0, 9}, {t, 0, 9}, {a, 1, 9}, {s, 0, 9}, {k, 0, 9}, {f,
1, 
    9}, {e, 0, 9}]

Bye
Ben


  • Prev by Date: Re: replacement rule and sparsearray question
  • Next by Date: Re: List difference using patterns and substitutions.
  • Previous by thread: Re: Arithmetic Puzzle (so simple it's hard)
  • Next by thread: Re: Arithmetic Puzzle (so simple it's hard)