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Re: replacement rule and sparsearray question


Arkadiusz.Majka at gmail.com wrote:
> Hi,
> 
> How can I apply a replacement rule to sparse array, e.g
> 
> SparseArray[{1,2,3}]/.{2->222}
> 
> and obtain the same result as for {1,2,3}/.{2->222} (what is {1,222,3}.
> 
> I DON'T want to call Normal before.
> 
> Thanks,
> 
> arek
> 

SparseArray[{1, 2, 3} /. {2 -> 222}];
FullForm[%]
MatrixForm[%]

--> SparseArray[Automatic,List[3],0,List[1,List[List[0,3],List[List[
   1],List[2],List[3]]],List[1,222,3]]]

Regards,
Jean-Marc


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