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RE: Function defined with If

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  • Subject: [mg71382] RE: [mg71338] Function defined with If
  • From: "David Park" <djmp at>
  • Date: Thu, 16 Nov 2006 00:53:24 -0500 (EST)


I'm not quite certain what you want to do. Suppose that a and b are
complicated expressions of x and y. Do you want f to be a function of x and
y, or of a and b? I am going to assume a function of x and y.

Then note the Attributes of If.

{HoldRest, Protected}

So in the f definition we have to evaluate the second and third arguments of

a = x; b = y;
f[x_, y_] = If[a < b, Evaluate@a, Evaluate@b]
If[x < y, x, y]

David Park
djmp at

From: Julian Aguirre [mailto:julian.aguirre at]

Dear group,

I am trying to define a function of the variables x, y through other
quantities depending on x and y and the function If. A minimal example

In[1]:a = x;
b = y;
f[ x_, y_ ] = If[ a < b, a, b ]
Out[3]If[ x < y, a, b ]

How can I force Mathematica to return If[ x < y, x, y ], as I thought
it would?

Thaks in advance,

Julián Aguirre

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