1`2 == 1*^-10

*To*: mathgroup at smc.vnet.net*Subject*: [mg71525] 1`2 == 1*^-10*From*: "Andrew Moylan" <andrew.j.moylan at gmail.com>*Date*: Wed, 22 Nov 2006 05:22:08 -0500 (EST)

Hi all, Please help me understand the following behaviour, which was wrecking havoc the results I get from calling the function Sort: Evaluating 1`2 == 1*^-10 gives True Correspondingly, evaluating each of 1`2 < 1*^-10 and 1`2 > 1*^-10 give False Can anyone explain why these two numbers are declared to be equal? It's inconsistent with my previous understanding of how arbitrary-precision numbers are interpreted in Mathematica. (I've resolved my sorting problem by using OrderedQ instead of Less as the ordering function in Sort. But why was this necessary?) Cheers, Andrew

**Follow-Ups**:**Re: Re: 1`2 == 1*^-10***From:*"Chris Chiasson" <chris@chiasson.name>

**Re: Re: 1`2 == 1*^-10***From:*"Chris Chiasson" <chris@chiasson.name>

**Re: 1`2 == 1*^-10***From:*Andrzej Kozlowski <akoz@mimuw.edu.pl>