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Re: AGAIN Nested while loop!!!


THANKS VERY MUCH


It is so amazing that how many different ways one can write a program
in mathematica! But still the while and for ( traditional loops) is
much faster.


While loop in this case is faster since doesn't need a break[]!!

Thanks to all of you guys ESPECIALLY DANIEL!

regards,

chekad






On 11/24/06, Bob Hanlon <hanlonr at cox.net> wrote:
> lst = Table[Random[Integer, {i, 50}], {i, 6}]
>
> {11,30,44,28,50,31}
>
> So that the result has a consistent structure in either case, I would recommend that the output be {True, {}} or {False, {pairs}}
>
> Needs["DiscreteMath`Combinatorica`"];
>
> Module[{sel=Select[KSubsets[lst,2],
>        Mod[#.#,5]==0&]},
>  {Length[sel]==0,sel}]
>
> {False, {{11, 28}, {30, 50}, {44, 28}, {28, 31}}}
>
>
> Bob Hanlon
>
> ---- mumat <csarami at gmail.com> wrote:
> > I have a list of numbers
> >
> > lst = Table[Random[Integer, {i, 50}], {i, 6}]
> >
> > I want to write a program that if There are two numbers x, y in A where
> >
> >
> > Mod[x^2+y^2, 5]==0  reuturn False and the pair {x,y}, otherwise True!
> >
> >
> > For[i = 0, i < 6, For[j = i, j < 6,
> >   If[Mod[lst[[i]]^2 + lst[[j]]^2, 3] == 0,
> > Return[False,{i,j}]];Break[], j++], i++]
> >
> > While loop and nested while loops accept only one counter "i".
> >
> > i=1;j=2;
> >
> > While[i<6 && While[j<6 &&
> > Mod[lst[[i]]^2+lst[[j]]^2,7]=!=0,j++];i++];{i,j}
> >
> > {2,6}
> >
> >
> > Would be great if you could help me with this!!
> >
> >
> > Regards,
> >
> > chekad
> >
>
>


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