ReplaceAll (/.)
- To: mathgroup at smc.vnet.net
- Subject: [mg69197] ReplaceAll (/.)
- From: Bruce Colletti <vze269bv at verizon.net>
- Date: Fri, 1 Sep 2006 06:41:51 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Re Mathematica 5.2.0.0.
Why doesn't:
(a b) /. x_Times -> List @@ x
return {a,b}? My (flawed) reasoning is that a b has form Times[a,b], and so x matches to Times[a,b]. List@@x replaces Times with List to yield List[a,b], or {a,b}...or so it would seem.
The explanation is somehow linked to the fact that:
(a b) /. x_Times :> List @@ x
returns {a,b}, but I don't see why this works but not the above.
Although List@@(a,b) returns {a,b}, I want to use the above ReplaceAll function (this example here is taken from a larger problem).
Thankx.
Bruce
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