RE: plot help

*To*: mathgroup at smc.vnet.net*Subject*: [mg69324] RE: [mg69306] plot help*From*: "David Park" <djmp at earthlink.net>*Date*: Thu, 7 Sep 2006 04:30:11 -0400 (EDT)

I think that PlotRange is the best way to do it. David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: dimmechan at yahoo.com [mailto:dimmechan at yahoo.com] To: mathgroup at smc.vnet.net Hi to all. I have the following simple plot. \!\(Plot[{1/x, \(-1\)/x}, {x, 0, 5}, Axes -> False, Frame -> True, PlotStyle -> {AbsoluteThickness[1], AbsoluteThickness[ 2]}, ImageSize -> {600, 300}, PlotLegend -> {f\_1[x], f\_2[x]}, \ LegendShadow -> None, LegendPosition -> {0, 0.2}, LegendSize -> {1, 0.3}, FrameTicks -> {{0, {0.5, "\<\>"}, 1, {1.5, "\<\>"}, 2, {2.5, "\<\>"}, 3, {3.5, "\<\>"}, 4, {4.5, "\<\>"}, 5}, {\(-20\), {\(-15\), "\<\>"}, \ \(-10\), {\(-5\), "\<\>"}, 0, {5, "\<\>"}, 10, {15, "\<\>"}, 20}, None, None}]\) Executing the command I get a nice plot but what I really is the frame to begin at zero and not left from zero. I tried PlotRange (see below) and I got sth close to what I need but I wonder if there is a more elegant solution. \!\(Plot[{1/x, \(-1\)/x}, {x, 0, 5}, Axes -> False, Frame -> True, PlotStyle -> {AbsoluteThickness[1], AbsoluteThickness[ 2]}, ImageSize -> {600, 300}, PlotLegend -> {f\_1[x], f\_2[x]}, \ LegendShadow -> None, LegendPosition -> {0, 0.2}, LegendSize -> {1, 0.3}, FrameTicks -> {{0, {0.5, "\<\>"}, 1, {1.5, "\<\>"}, 2, {2.5, "\<\>"}, 3, {3.5, "\<\>"}, 4, {4.5, "\<\>"}, 5}, {\(-20\), {\(-15\), "\<\>"}, \ \(-10\), {\(-5\), "\<\>"}, 0, {5, "\<\>"}, 10, {15, "\<\>"}, 20}, None, None}, PlotRange -> {{\(- .001\), 5}, {\(-25\), 25}}]\) Thanks in advance for any help