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Re: mapping of function


Hi,
MapAT does not seem to be a very convenient solution because you have to 
bother about positions. Mathematica can do this on its own by pattern 
matching. E.g.:
exp1 /. {x -> Sin[x], y -> Cos[x]}
Daniel

dimmechan at yahoo.com wrote:
> Hello.
> 
> I am working on John Gray's Book Mastering Mathematica.
> 
> Here is one simple expression.
> 
> exp1 = x^3 + (1 + z)^2
> x^3 + (1 + z)^2
> 
> I am thinking of ways to map the sine function only to {x,z}.
> Here are some alternatives I considered.
> 
> MapAt[Sin, exp1, Flatten[(Position[exp1, #1] & ) /@ Variables[exp1],
> 1]]
> Sin[x]^3 + (1 + Sin[z])^2
> 
> MapAt[Sin, exp1, Position[exp1, _Symbol, Heads -> False]]
> Sin[x]^3 + (1 + Sin[z])^2
> 
> Are there any other possibilities?
> 
> Thanks for any response.
> 


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