Re: equation question

*To*: mathgroup at smc.vnet.net*Subject*: [mg69939] Re: equation question*From*: dh <dh at metrohm.ch>*Date*: Thu, 28 Sep 2006 06:14:26 -0400 (EDT)*References*: <efdk51$qg$1@smc.vnet.net>

Hi Dimitris, you can try "FindInstance". E.g:" FindInstance[{Sin[x]\[Equal]2,Re[x]>1.5},x]//N gives:{{x -> 1.5708 + 1.31696 \[ImaginaryI]}} Daniel dimmechan at yahoo.com wrote: > Hello. > > Consider the following simple examples of FindRoot application. > > FindRoot[Sin[x] == 2, {x, I}] > {x -> 1.5707963267948966 + 1.3169578969248168*I} > > FindRoot[Sin[x^2] == 2, {x, I + 1}] > {x -> 1.3454777060580754 + 0.4894016047219337*I} > > FindRoot[Sin[x^2] == 2, {x, 3*I + 2}] > {x -> 0.3004695589886017 + 2.1914997002654357*I} > > Is it possible for FindRoot (or in general in another way) to search > for solutions > in the complex plane in an particular domain e.g. searching in the > domain that > is made by the lines Re[x]=a1, Re[x]=a2 and Im[x]=b1, Im[b]=b2 ? > > I really appreciate any assistance. > > Regards > Dimitris >