       Re: equation question

• To: mathgroup at smc.vnet.net
• Subject: [mg69939] Re: equation question
• From: dh <dh at metrohm.ch>
• Date: Thu, 28 Sep 2006 06:14:26 -0400 (EDT)
• References: <efdk51\$qg\$1@smc.vnet.net>

```Hi Dimitris,
you can try "FindInstance". E.g:"
FindInstance[{Sin[x]\[Equal]2,Re[x]>1.5},x]//N
gives:{{x -> 1.5708 + 1.31696 \[ImaginaryI]}}

Daniel

dimmechan at yahoo.com wrote:
> Hello.
>
> Consider the following simple examples of FindRoot application.
>
> FindRoot[Sin[x] == 2, {x, I}]
> {x -> 1.5707963267948966 + 1.3169578969248168*I}
>
> FindRoot[Sin[x^2] == 2, {x, I + 1}]
> {x -> 1.3454777060580754 + 0.4894016047219337*I}
>
> FindRoot[Sin[x^2] == 2, {x, 3*I + 2}]
> {x -> 0.3004695589886017 + 2.1914997002654357*I}
>
> Is it possible for FindRoot (or in general in another way) to search
> for solutions
> in the complex plane in an particular domain e.g. searching in the
> domain that
> is made by the lines Re[x]=a1, Re[x]=a2 and Im[x]=b1, Im[b]=b2 ?
>
> I really appreciate any assistance.
>
> Regards
> Dimitris
>

```

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