subsets of a set
- To: mathgroup at smc.vnet.net
- Subject: [mg70003] subsets of a set
- From: dimmechan at yahoo.com
- Date: Sat, 30 Sep 2006 05:12:27 -0400 (EDT)
Actually it was more easily than I believed lst=Tuples[Range[7], 3]; Cases[Union[Union /@ lst], {_, _, _}] {{1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 2, 6}, {1, 2, 7}, {1, 3, 4}, {1,3, 5}, {1, 3, 6},{1, 3, 7}, {1, 4, 5}, {1, 4, 6}, {1, 4, 7}, {1, 5, 6}, {1, 5, 7}, {1,6, 7}, {2, 3, 4},{2, 3, 5}, {2, 3, 6}, {2, 3, 7}, {2, 4, 5}, {2, 4, 6}, {2, 4, 7}, {2,5, 6}, {2, 5, 7}, {2, 6, 7}, {3, 4, 5}, {3, 4, 6}, {3, 4, 7}, {3, 5, 6}, {3, 5, 7}, {3,6, 7}, {4, 5, 6},{4, 5, 7}, {4, 6, 7}, {5, 6, 7}} Anyway, I really appreciate your guidance for other approaches. BTW I discovered that (not big deal for you...but quite big for me!) Flatten[Outer[List, Range[7], Range[7], Range[7]], 2] == Tuples[Range[7], 3] True Also the following command gives all the sublsets of {1,2,3,4} (Cases[Union[Union /@ Tuples[Range[4], 4]], #1] & ) /@ Table[_, {i, 1, 4}, {j, 1, i}] {{{1}, {2}, {3}, {4}}, {{1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}}, {{1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}}, {{1, 2, 3, 4}}} Any other ideas to get the same output? Thanks in advance for any help. Dimitris Anagnostou