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Re: (Not trivial) Definite Integration of a rational function


On Apr 7, 11:05 am, Bhuvanesh <lalu_bh... at yahoo.com> wrote:
> Not necessarily. In this particular example Integrate uses a form of Newton-Leibniz.
>
> Bhuvanesh,
> Wolfram Research

Ok!
Thanks a lot for clearing this issue.

But, since Mathematica uses the Newton-Leibniz formula in this example
the question remains why it fails!

Anyway...
the developer version works porperly as you said and this sounds well!

Regards
Dimitris




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