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Re: Solving periodic functions

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  • Subject: [mg75004] Re: [mg74935] Solving periodic functions
  • From: Bob Hanlon <hanlonr at>
  • Date: Fri, 13 Apr 2007 02:19:23 -0400 (EDT)
  • Reply-to: hanlonr at




{{x -> Pi/2}, {x -> (3*Pi)/2}}

Bob Hanlon

---- David Rees <w3bdevilREMOVE at> wrote: 
> This is probably totally elementary, but I'm stumped nonetheless.
> Anyway, in Mathematica, how do I solve an equation with multiple periodic 
> functions within a given function domain bound?
> i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where 
> 0<x<=2Pi ?
> thanks 

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