Re: Solving periodic functions
- To: mathgroup at smc.vnet.net
- Subject: [mg75004] Re: [mg74935] Solving periodic functions
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Fri, 13 Apr 2007 02:19:23 -0400 (EDT)
- Reply-to: hanlonr at cox.net
Needs["Graphics`"];
Plot[6Cos[x]-5Cos[x],{x,0,2Pi},Ticks->{PiScale,Automatic}];
{Reduce[{6Cos[x]-5Cos[x]==0,0<x<=2Pi},x]//ToRules}
{{x -> Pi/2}, {x -> (3*Pi)/2}}
Bob Hanlon
---- David Rees <w3bdevilREMOVE at THISw3bdevil.com> wrote:
> This is probably totally elementary, but I'm stumped nonetheless.
>
> Anyway, in Mathematica, how do I solve an equation with multiple periodic
> functions within a given function domain bound?
>
> i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where
> 0<x<=2Pi ?
>
> thanks