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Re: Solving periodic functions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75004] Re: [mg74935] Solving periodic functions
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Fri, 13 Apr 2007 02:19:23 -0400 (EDT)
  • Reply-to: hanlonr at cox.net

Needs["Graphics`"];

Plot[6Cos[x]-5Cos[x],{x,0,2Pi},Ticks->{PiScale,Automatic}];

{Reduce[{6Cos[x]-5Cos[x]==0,0<x<=2Pi},x]//ToRules}

{{x -> Pi/2}, {x -> (3*Pi)/2}}


Bob Hanlon

---- David Rees <w3bdevilREMOVE at THISw3bdevil.com> wrote: 
> This is probably totally elementary, but I'm stumped nonetheless.
> 
> Anyway, in Mathematica, how do I solve an equation with multiple periodic 
> functions within a given function domain bound?
> 
> i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where 
> 0<x<=2Pi ?
> 
> thanks 



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