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Re: Solving periodic functions

• To: mathgroup at smc.vnet.net
• Subject: [mg75006] Re: Solving periodic functions
• From: "Drago Ganic" <dganic at vodatel.net>
• Date: Sat, 14 Apr 2007 01:03:18 -0400 (EDT)
• References: <evkroh$o0k$1@smc.vnet.net>

Hi David,
use Reduce ...
Reduce[ 6 Cos[x] - 5 Cos[x] == 0 && 0 < x <= 2Pi , x]
x == Pi/2 || x == (3*Pi)/2

This is *not* elementary functionality. Historically, it was not available 
until recently (Version 5.0) in Mathematica.

Greeting from Croatia,
Drago

"David Rees" <w3bdevilREMOVE at THISw3bdevil.com> wrote in message 
news:evkroh$o0k$1 at smc.vnet.net...
> This is probably totally elementary, but I'm stumped nonetheless.
>
> Anyway, in Mathematica, how do I solve an equation with multiple periodic
> functions within a given function domain bound?
>
> i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where
> 0<x<=2Pi ?
>
> thanks
>
>
>