Re: Solving periodic functions

*To*: mathgroup at smc.vnet.net*Subject*: [mg75006] Re: Solving periodic functions*From*: "Drago Ganic" <dganic at vodatel.net>*Date*: Sat, 14 Apr 2007 01:03:18 -0400 (EDT)*References*: <evkroh$o0k$1@smc.vnet.net>

Hi David, use Reduce ... Reduce[ 6 Cos[x] - 5 Cos[x] == 0 && 0 < x <= 2Pi , x] x == Pi/2 || x == (3*Pi)/2 This is *not* elementary functionality. Historically, it was not available until recently (Version 5.0) in Mathematica. Greeting from Croatia, Drago "David Rees" <w3bdevilREMOVE at THISw3bdevil.com> wrote in message news:evkroh$o0k$1 at smc.vnet.net... > This is probably totally elementary, but I'm stumped nonetheless. > > Anyway, in Mathematica, how do I solve an equation with multiple periodic > functions within a given function domain bound? > > i.e. How would I find all values of x given 6Cos[x]-5Cos[x] = 0 where > 0<x<=2Pi ? > > thanks > > >