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Re: Mathematica help

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75057] Re: [mg75035] Mathematica help
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Mon, 16 Apr 2007 04:06:26 -0400 (EDT)
  • Reply-to: hanlonr at cox.net

Use ImplicitPlot or Solve the equation

Needs["Graphics`"];

ImplicitPlot[x^2y^3-y^4==1,{x,-3,3},
    AspectRatio->1,ImageSize->288];

Off[Plot::plnr];
Plot[Evaluate[y/.
        Solve[x^2y^3-y^4==1,y][[{3,4}]]],
    {x,-3,3},AspectRatio->1,
    PlotStyle->{Blue,Red}];


Bob Hanlon

---- liltammer4 at aol.com wrote: 
> I don't know how to graph the curve x^2y^3-y^4=1 for x ranging from -3
> to 3.
> Here is what I have and I don't understand what the problem is???
> 
> Plot[x^2 y^3 - y^4 == 1, {x, -3, 3}]
> 
> 



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