Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2007
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: ImplicitPlot errors

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75095] Re: [mg75066] ImplicitPlot errors
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Mon, 16 Apr 2007 20:20:10 -0400 (EDT)
  • Reply-to: hanlonr at cox.net

Your variable y has been assigned a value. Clear or Remove your variables or start with a fresh kernel.


Bob Hanlon

---- David Rees <w3bdevilREMOVE at THISw3bdevil.com> wrote: 
> Hi,
> 
> I've been trying to get ImplicitPlot to plot an implicit function (naturally 
> ;) ), but it throws errors to cryptic for me, even when copying and pasting 
> from the Mathematica function reference.
> 
> In[40]:= ImplicitPlot[{x^2 + x*y + y^2 == 7, y == 2*Sqrt[7/3]}, {x, -5, 5}]
> 
> ImplicitPlot::var :
> 
> Equation x^2+x 
> Function[x,x^2+2xy-3y^2-16]+Function[x,x^2+2xy-3<<1>>-16]^2==7 does not have 
> a single variable other than x
> 
> ImplicitPlot::var :
> 
> Equation Function[x,x^2+2xy-3y^2-16]==2Sqrt(7/3) does not have a single 
> variable other than x
> 
> Out[40]:=\!\(ImplicitPlot[{x\^2 + x\ Function[x, x\^2 + 2\
>           xy - 3\ y\^2 - 16] + Function[
>               x, x\^2 + 2\ xy - 3\ y\^2 - 16]\^2 == 7, Function[x, x\^2 + 2\
>               xy - 3\ y\^2 - 16] == 2\ \@\(7\/3\), x == 2\ \@\(7\/3\)}, {x, 
> \
> \(-5\), 5}, {Function[x, x\^2 + 2\ xy - 3\ y\^2 - 16], \(-5\), 5}]\)
> 
> 
> 
> What am I doing wrong? Even ImplicitPlot[x+y==2,{x,-4,4}] fails.
> 
> Thanks



  • Prev by Date: Re: ImplicitPlot errors
  • Next by Date: Re: differentiate a function of a function
  • Previous by thread: Re: Re: ImplicitPlot errors
  • Next by thread: Re: ImplicitPlot errors