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MathGroup Archive 2007

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Re: ImplicitPlot errors

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75082] Re: ImplicitPlot errors
  • From: "Norbert Marxer" <marxer at mec.li>
  • Date: Mon, 16 Apr 2007 20:13:31 -0400 (EDT)
  • References: <evvbfs$9q5$1@smc.vnet.net>

On 16 Apr., 10:18, "David Rees" <w3bdevilREM... at THISw3bdevil.com>
wrote:
> Hi,
>
> I've been trying to get ImplicitPlot to plot an implicit function (naturally
> ;) ), but it throws errors to cryptic for me, even when copying and pasting
> from the Mathematica function reference.
>
> In[40]:= ImplicitPlot[{x^2 + x*y + y^2 == 7, y == 2*Sqrt[7/3]}, {x, -5, 5}]
>
> ImplicitPlot::var :
>
> Equation x^2+x
> Function[x,x^2+2xy-3y^2-16]+Function[x,x^2+2xy-3<<1>>-16]^2==7 does not have
> a single variable other than x
>
> ImplicitPlot::var :
>
> Equation Function[x,x^2+2xy-3y^2-16]==2Sqrt(7/3) does not have a single
> variable other than x
>
> Out[40]:=\!\(ImplicitPlot[{x\^2 + x\ Function[x, x\^2 + 2\
>           xy - 3\ y\^2 - 16] + Function[
>               x, x\^2 + 2\ xy - 3\ y\^2 - 16]\^2 == 7, Function[x, x\^2 + 2\
>               xy - 3\ y\^2 - 16] == 2\ \@\(7\/3\), x == 2\ \@\(7\/3\)}, {x,
> \
> \(-5\), 5}, {Function[x, x\^2 + 2\ xy - 3\ y\^2 - 16], \(-5\), 5}]\)
>
> What am I doing wrong? Even ImplicitPlot[x+y==2,{x,-4,4}] fails.
>
> Thanks


Hello

Your symbol y was set to Function[x, x^2 + 2xy - 3y^2 - 16]

If you use Clear[y] before calling ImplicitPlot[...] everything will
work.

Best Regards
Norbert Marxer




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