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MathGroup Archive 2007

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Re: ImplicitPlot errors

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75147] Re: ImplicitPlot errors
  • From: dimitris <dimmechan at yahoo.com>
  • Date: Wed, 18 Apr 2007 05:08:01 -0400 (EDT)
  • References: <evvbfs$9q5$1@smc.vnet.net><f0142t$8n5$1@smc.vnet.net>

Hi Andrzej.

Simply I can't remember it if I have discovered it by myself or see
somewhere.

Sorry but my memory does not help here!

Dimitris


Andrzej Kozlowski <akoz at mimuw.edu.pl> wrote:

On 17 Apr 2007, at 09:16, dimitris wrote:

> Hi.
>
> Quit;
>

Is Quit documented anywhere or you just discover it by accident? Quit
[] is of course a documented Mathematica function while Quit seems to
be an undocumented symbol. To me the fact that it works seems
illogical and aesthetically displeasing. (The same applies to Exit[]
and Exit).

Andrzej Kozlowski



=CF/=C7 dimitris =DD=E3=F1=E1=F8=E5:
> Hi.
>
> Quit;
>
> << "Graphics`ImplicitPlot`"
>
> ImplicitPlot[{x^2 + x*y + y^2 == 7, y == 2*Sqrt[7/3]}, {x, -5, 5}]
> (*works*)
>
> ImplicitPlot[x+y==2,{x,-4,4}]
> (*works*)
>
> Dimitris
>
>
> =CF/=C7 David Rees =DD=E3=F1=E1=F8=E5:
> > Hi,
> >
> > I've been trying to get ImplicitPlot to plot an implicit function (natu=
ra=
> lly
> > ;) ), but it throws errors to cryptic for me, even when copying and pas=
ti=
> ng
> > from the Mathematica function reference.
> >
> > In[40]:= ImplicitPlot[{x^2 + x*y + y^2 == 7, y == 2*Sqrt[7/3]=
},=
>  {x, -5, 5}]
> >
> > ImplicitPlot::var :
> >
> > Equation x^2+x
> > Function[x,x^2+2xy-3y^2-16]+Function[x,x^2+2xy-3<<1>>-16]^2==7 does=
 n=
> ot have
> > a single variable other than x
> >
> > ImplicitPlot::var :
> >
> > Equation Function[x,x^2+2xy-3y^2-16]==2Sqrt(7/3) does not have a si=
ng=
> le
> > variable other than x
> >
> > Out[40]:=\!\(ImplicitPlot[{x\^2 + x\ Function[x, x\^2 + 2\
> >           xy - 3\ y\^2 - 16] + Function[
> >               x, x\^2 + 2\ xy - 3\ y\^2 - 16]\^2 == 7, Function[x, =
x\=
> ^2 + 2\
> >               xy - 3\ y\^2 - 16] == 2\ \@\(7\/3\), x == 2\ \@\(=
7\=
> /3\)}, {x,
> > \
> > \(-5\), 5}, {Function[x, x\^2 + 2\ xy - 3\ y\^2 - 16], \(-5\), 5}]\)
> >
> >
> >
> > What am I doing wrong? Even fails.
> >
> > Thanks



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