MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Assign delayed but fixed value

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75214] Re: Assign delayed but fixed value
  • From: dh <dh at metrohm.ch>
  • Date: Fri, 20 Apr 2007 00:46:11 -0400 (EDT)
  • References: <f079pm$47d$1@smc.vnet.net>


Hi Istvan,

try:

param=.;var=.;

var:=var=Table[Random[Integer,{0,3}],{param}];

hope this helps, Daniel



zac wrote:

> Dear Group!

> 

> My target is to define the value of 'var' in terms of the value of

> 'param'. The problem is that 'param' is introduced later than 'var',

> and this time-sequence cannot be changed. However, I would like to

> create 'var' such a way that IF 'param' is known, the value of 'var'

> should be the same any time it is called.

> Example code:

> 

> In[1]:=

> var = Table[Random[Integer,{0,3}],{param}];

> param = 3;

> 

>>From In[1]:= Table::iterb : Iterator {param} does not have appropriate

> bounds. More...

> 

> In[3]:=

> var

> 

> Out[3]=

> {1,1,3}

> 

> In[4]:=

> var

> 

> Out[4]=

> {0,3,1}

> 

> 

> The Table::iterb message is a secondary matter, as the two 'var'

> outputs do not equal, and this is my primary concern. Any idea how to

> solve this task? Thanks in advance.

> 

> Istvan

> 

> 




  • Prev by Date: Re: Interpreting the solutions
  • Next by Date: Re: Assign delayed but fixed value
  • Previous by thread: Re: Assign delayed but fixed value
  • Next by thread: Re: Assign delayed but fixed value