Re: Another question on lists
- To: mathgroup at smc.vnet.net
- Subject: [mg80641] Re: [mg80618] Another question on lists
- From: DrMajorBob <drmajorbob at bigfoot.com>
- Date: Tue, 28 Aug 2007 02:03:46 -0400 (EDT)
- References: <27088617.1188205442155.JavaMail.root@m35>
- Reply-to: drmajorbob at bigfoot.com
Here's an example: sample = Array[ RandomInteger[{1, 10}, {RandomInteger[{3, 10}]}] &, {15}] Length /@ % {{5, 7, 7, 1, 2, 5, 2, 7, 3}, {3, 4, 3, 8, 8}, {1, 4, 6, 6, 1, 6, 3}, {4, 6, 1, 9, 9, 7, 3, 5, 10}, {9, 1, 4, 2, 7, 1, 5}, {2, 8, 2, 4, 7, 3, 8}, {2, 10, 4, 7, 2, 10, 3}, {10, 5, 10, 6, 5, 10, 4, 3, 4}, {5, 2, 3, 10, 8}, {5, 1, 7}, {1, 5, 8, 4, 8, 5, 8, 2}, {3, 3, 8, 5, 1, 7}, {6, 10, 1, 6, 3, 5, 7, 6, 1, 7}, {3, 5, 1, 6, 6}, {10, 10, 9, 3, 9}} {9, 5, 7, 9, 7, 7, 7, 9, 5, 3, 8, 6, 10, 5, 5} Last@SortBy[sample, Length] {6, 10, 1, 6, 3, 5, 7, 6, 1, 7} or sample[[Ordering[sample, -1, Length[#1] < Length[#2] &]]] {{6, 10, 1, 6, 3, 5, 7, 6, 1, 7}} Bobby On Sun, 26 Aug 2007 22:20:22 -0500, Mauricio Esteban Cuak <cuak2000 at gmail.com> wrote: > Hello again.Thank you very much for your previous help. However, I > seem to stumble on another rock: > > I have a list of n sub-lists with different number of elements. I > want to select the list with the highest number of elements. > I tried to combine the Select function with Lenght but couldn't do it: > > Select[list, Length /@ list >= Max[Length /@ list] &] > > Thanks for reading. > > Regards, > > cd > > P.D.: Any tips,websites, books, on how to learn some basic programming > on Mathematica? > I'm slowly beginning to read "The Mathematica Book"...should I just > concentrate on that? > > -- DrMajorBob at bigfoot.com
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