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Re: how draw box with open front

  • To: mathgroup at smc.vnet.net
  • Subject: [mg83873] Re: how draw box with open front
  • From: Yves Klett <yves.klett at googlemail.com>
  • Date: Mon, 3 Dec 2007 05:46:25 -0500 (EST)
  • References: <fior1b$d0u$1@smc.vnet.net> <200712011050.FAA28421@smc.vnet.net> <fitspu$5qd$1@smc.vnet.net>

Murray,

I get the same the spurious lines in the exported EPS in V6. If you
copy&paste the graphics into e.g. OpenOffice Draw, then the artifacts
are not there (although the tesselation of the pasted polygons is very
different from v5). You might want to use the v5 graphics engine with

<< Version5`Graphics`

but then again I have trouble exporting the graphics object with this one...

The scaling issue can e.g. be easily addressed with a rule:

Normal[PolyhedronData["Cube"]][[1, 1]]
% /. {x_?NumericQ, y_?NumericQ, z_?NumericQ} :> {1 x, 2 y, 3 z}
Graphics3D[{Most[%]}]

Regards,
Yves


Murray Eisenberg schrieb:
> Aside from the limitation I describe in a separate reply about my need 
> to scale one dimension, this method has the same defect I described in 
> :  spurious artifacts of grid lines across the faces when I 
> export the graphic to EPS.
> 
> Yves Klett wrote:
>> Murray Eisenberg schrieb:
>>> In Mathematica 6, what's the best way to draw a convincing box 
>>> (rectangular parallelepiped) with an open front?
>>>
>>> Of course I tried Cuboid, but no matter how I try to treat the faces, it 
>>> still looks like the front is solid, too.
>>>
>> Hi Murray,
>>
>> perhaps I am missing something, but why not use a set of Polygons as faces?
>>
>> For example:
>>
>> Normal[PolyhedronData["Cube"]][[1, 1]]
>> Most[%] // Graphics3D
>>
>>
>> shows a cube with one face removed in V6.
>>
>> Regards,
>> Yves
>>
> 


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