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Re: Re: how draw box with open front

  • To: mathgroup at smc.vnet.net
  • Subject: [mg83834] Re: [mg83825] Re: how draw box with open front
  • From: Murray Eisenberg <murray at math.umass.edu>
  • Date: Sun, 2 Dec 2007 04:04:16 -0500 (EST)
  • Organization: Mathematics & Statistics, Univ. of Mass./Amherst
  • References: <fior1b$d0u$1@smc.vnet.net> <200712011050.FAA28421@smc.vnet.net>
  • Reply-to: murray at math.umass.edu

The box is to have a square box but it should have a different, shorter, 
depth than the length of sides of the back.  I don't know how to do that 
with PolyhedronData["Cube"].  Where, how do I scale the dimensions -- 
without directly editing the individual vertices in the constituent 
polygons resulting from Most[Normal[PolyhedronData["Cube"]][[1, 1]]].


Yves Klett wrote:
> Murray Eisenberg schrieb:
>> In Mathematica 6, what's the best way to draw a convincing box 
>> (rectangular parallelepiped) with an open front?
>>
>> Of course I tried Cuboid, but no matter how I try to treat the faces, it 
>> still looks like the front is solid, too.
>>
> Hi Murray,
> 
> perhaps I am missing something, but why not use a set of Polygons as faces?
> 
> For example:
> 
> Normal[PolyhedronData["Cube"]][[1, 1]]
> Most[%] // Graphics3D
> 
> 
> shows a cube with one face removed in V6.
> 
> Regards,
> Yves
> 

-- 
Murray Eisenberg                     murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower      phone 413 549-1020 (H)
University of Massachusetts                413 545-2859 (W)
710 North Pleasant Street            fax   413 545-1801
Amherst, MA 01003-9305


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