Re: Re: how draw box with open front

*To*: mathgroup at smc.vnet.net*Subject*: [mg83834] Re: [mg83825] Re: how draw box with open front*From*: Murray Eisenberg <murray at math.umass.edu>*Date*: Sun, 2 Dec 2007 04:04:16 -0500 (EST)*Organization*: Mathematics & Statistics, Univ. of Mass./Amherst*References*: <fior1b$d0u$1@smc.vnet.net> <200712011050.FAA28421@smc.vnet.net>*Reply-to*: murray at math.umass.edu

The box is to have a square box but it should have a different, shorter, depth than the length of sides of the back. I don't know how to do that with PolyhedronData["Cube"]. Where, how do I scale the dimensions -- without directly editing the individual vertices in the constituent polygons resulting from Most[Normal[PolyhedronData["Cube"]][[1, 1]]]. Yves Klett wrote: > Murray Eisenberg schrieb: >> In Mathematica 6, what's the best way to draw a convincing box >> (rectangular parallelepiped) with an open front? >> >> Of course I tried Cuboid, but no matter how I try to treat the faces, it >> still looks like the front is solid, too. >> > Hi Murray, > > perhaps I am missing something, but why not use a set of Polygons as faces? > > For example: > > Normal[PolyhedronData["Cube"]][[1, 1]] > Most[%] // Graphics3D > > > shows a cube with one face removed in V6. > > Regards, > Yves > -- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower phone 413 549-1020 (H) University of Massachusetts 413 545-2859 (W) 710 North Pleasant Street fax 413 545-1801 Amherst, MA 01003-9305

**References**:**Re: how draw box with open front***From:*Yves Klett <yves.klett@googlemail.com>