Services & Resources / Wolfram Forums / MathGroup Archive

MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

RE: different eigenvectors

  • To: mathgroup at
  • Subject: [mg83921] RE: [mg83883] different eigenvectors
  • From: "Jaccard Florian" <Florian.Jaccard at>
  • Date: Tue, 4 Dec 2007 04:30:43 -0500 (EST)
  • References: <>


Eigenvectors just give the directions!
As you know, if v is an eigenvector of the matrix A, you have : 
A*v=lambda*v, where lambda is the eigenvalue associated to v.

If you take another vector with the same direction, for example -3*v, it 
is also an eigenvector associated to lambda, because 

So, if you take another system, you surely can obtain another vector!

If two vectors are associated to the same eigenvalue, let us say v and 
w, then all the combinaisons (like a*v+b*w) are eigenvectors. So it can 
become quite difficult to see that results are equivalent.

You have to see the eigenvectors as directions, and not vectors.
The important thing is to see what eigenvalue are associated to what 
collection of eigendirections.

The best thing is to use :


The first line are the eigenvalues, the second, in the same order, the 



-----Message d'origine-----
De=A0: vicky Al Aisa [mailto:vickyisai at]
Envoy=E9=A0: lundi, 3. d=E9cembre 2007 13:09
=C0=A0: mathgroup at
Objet=A0: [mg83883] different eigenvectors


I am using Eigenvectors function to calculate eigenvectors in
mathematica 5.2.
while comparing the results with the eigenvectors (of same matrix)
computed in another system, i found that both the results are bit =
with some values having opposite sign and coloumns rearranged.

thank you
viky al aisa

  • Prev by Date: Re: How to "unflatten"?
  • Next by Date: Notebook programming: SlideShow: emulating bullet at-a-time visibility
  • Previous by thread: different eigenvectors
  • Next by thread: Re: different eigenvectors