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Re: Hi presision problem
- To: mathgroup at smc.vnet.net
- Subject: [mg84126] Re: [mg84098] Hi presision problem
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Mon, 10 Dec 2007 20:46:54 -0500 (EST)
- Reply-to: hanlonr at cox.net
x = 1 - Pi^(-InverseGammaRegularized[1, 0, 1 - 1/Sqrt[E]]);
x // N
0.4358104164522437
1 - Exp[N[Log[1 - x], 40]]
0.4358104164522437130519205484392274141559
Bob Hanlon
---- "Art=C5=ABras Acus" <acus at itpa.lt> wrote:
> Dear Group,
>
> How to calculate the expression with higher than machine precision?
> Mathematica 6 seems runs into serious problems (gives Inderetrminate)
>
> N[1 - Pi^(-InverseGammaRegularized[1, 0, 1 - 1/Sqrt[E]]) , 20]
>
>
> Sincerely, Arturas Acus
>
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