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Re: Hi presision problem


x = 1 - Pi^(-InverseGammaRegularized[1, 0, 1 - 1/Sqrt[E]]);

x // N

0.4358104164522437

1 - Exp[N[Log[1 - x], 40]]

0.4358104164522437130519205484392274141559


Bob Hanlon

---- "Art=C5=ABras Acus" <acus at itpa.lt> wrote:
> Dear Group,
>
> How to calculate the expression with higher than machine precision?
> Mathematica 6 seems runs into serious problems (gives Inderetrminate)
>
> N[1 - Pi^(-InverseGammaRegularized[1, 0, 1 - 1/Sqrt[E]]) , 20]
>
>
> Sincerely, Arturas Acus
>



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