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Re: how fill PolarPlot?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg84433] Re: how fill PolarPlot?
*From*: Helen Read <hpr at together.net>
*Date*: Mon, 24 Dec 2007 04:44:45 -0500 (EST)
*References*: <fkla2t$3sh$1@smc.vnet.net>
*Reply-to*: HPR <read at math.uvm.edu>
Murray Eisenberg wrote:
> I Mathematica 6 I have a PolarPlot, e.g., a 4-leaved rose:
>
> PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}]
>
> How can I fill the inside -- or, what I really want, just the leaf in
> the right half-plane -- with some color?
>
> I note that Filling does not seem to be an option for PolarPlot (or for
> what would be almost as good, ParametricPlot).
>
> I tried including the following (obtained by converting from :
>
> Prolog->RegionPlot[(x^2 + y^2)^(3/2) <= x^2-y^2, {x,-0.02,1},{y,-1,1},
> Frame->False, AspectRatio->Automatic]
>
> However, that led to a mysterious error message:
>
> $Aborted is not a Graphics primitive or directive.
I got the even more mysterious error "Graphics is not a Graphics
primitive or directive".
> (Perhaps because of an incompatibility of a Prolog with cartesian
> coordinates inside a polar coordinate plot??)
Don't know, but in any case the following works.
Show[PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}],
RegionPlot[(x^2 + y^2)^(3/2) <= x^2 - y^2, {x, -0.02, 1}, {y, -1, 1},
Frame -> False, AspectRatio -> Automatic]]
--
Helen Read
University of Vermont
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