Re: how fill PolarPlot?

*To*: mathgroup at smc.vnet.net*Subject*: [mg84433] Re: how fill PolarPlot?*From*: Helen Read <hpr at together.net>*Date*: Mon, 24 Dec 2007 04:44:45 -0500 (EST)*References*: <fkla2t$3sh$1@smc.vnet.net>*Reply-to*: HPR <read at math.uvm.edu>

Murray Eisenberg wrote: > I Mathematica 6 I have a PolarPlot, e.g., a 4-leaved rose: > > PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}] > > How can I fill the inside -- or, what I really want, just the leaf in > the right half-plane -- with some color? > > I note that Filling does not seem to be an option for PolarPlot (or for > what would be almost as good, ParametricPlot). > > I tried including the following (obtained by converting from : > > Prolog->RegionPlot[(x^2 + y^2)^(3/2) <= x^2-y^2, {x,-0.02,1},{y,-1,1}, > Frame->False, AspectRatio->Automatic] > > However, that led to a mysterious error message: > > $Aborted is not a Graphics primitive or directive. I got the even more mysterious error "Graphics is not a Graphics primitive or directive". > (Perhaps because of an incompatibility of a Prolog with cartesian > coordinates inside a polar coordinate plot??) Don't know, but in any case the following works. Show[PolarPlot[Cos[2 theta], {theta, 0, 2 Pi}], RegionPlot[(x^2 + y^2)^(3/2) <= x^2 - y^2, {x, -0.02, 1}, {y, -1, 1}, Frame -> False, AspectRatio -> Automatic]] -- Helen Read University of Vermont