Re: Passing a list as seperate parameters?
- To: mathgroup at smc.vnet.net
- Subject: [mg73247] Re: [mg73194] Passing a list as seperate parameters?
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Thu, 8 Feb 2007 03:47:37 -0500 (EST)
- Reply-to: hanlonr at cox.net
m={{c,d},{a,b},{e,e},{c,d}};
Union[m]
{{a,b},{c,d},{e,e}}
Union@@m
{a,b,c,d,e}
Union/@m
{{c,d},{a,b},{e},{c,d}}
Bob Hanlon
---- Azumanga <4zumanga at gmail.com> wrote:
> I have a recuring problem in using mathematica, which I'm sure there
> must be a simple fix for, but I've looked through the manual and can't
> find it.
>
> As an example, I build up the list { {a,b},{c,d} }, and I want to find
> the union of it's elements.
>
> At first glance, I want Union. However, Union wants it's input as
> Union[{a,b},{c,d}], Union[{{a,b},{c,d}}] doesn't do anything.
>
> In general I get around this by fold, but it seems there should be a
> simpler method?
>