Re: Passing a list as seperate parameters?

*To*: mathgroup at smc.vnet.net*Subject*: [mg73247] Re: [mg73194] Passing a list as seperate parameters?*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Thu, 8 Feb 2007 03:47:37 -0500 (EST)*Reply-to*: hanlonr at cox.net

m={{c,d},{a,b},{e,e},{c,d}}; Union[m] {{a,b},{c,d},{e,e}} Union@@m {a,b,c,d,e} Union/@m {{c,d},{a,b},{e},{c,d}} Bob Hanlon ---- Azumanga <4zumanga at gmail.com> wrote: > I have a recuring problem in using mathematica, which I'm sure there > must be a simple fix for, but I've looked through the manual and can't > find it. > > As an example, I build up the list { {a,b},{c,d} }, and I want to find > the union of it's elements. > > At first glance, I want Union. However, Union wants it's input as > Union[{a,b},{c,d}], Union[{{a,b},{c,d}}] doesn't do anything. > > In general I get around this by fold, but it seems there should be a > simpler method? >